MathML Pythagorean Theorem

$a^{2} + b^{2} = c^{2}$

Podemos demostrar el teorema algebraicamente mostrando que el area del cuadrado grande es igual al area del cuadrado interno (hipotenusa al cuadrado) mas el area de los cuatro triangulos:

\begin{matrix} {(a + b)}^{2} & = & c^{2} + 4 \cdot (\frac{1}{2} a b) \\ a^{2} + 2 a b + b^{2} & = & c^{2} + 2 a b \\ a^{2} + b^{2} & = & c^{2} \end{matrix}

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This page was last modified on 21 mar 2025 by MDN contributors.

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